Tutor MathsGuru: Ask me for your burning Maths questions!
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SoWoW:
(Called algebraic number equations)Hi, i have one question.
Miss Tan wants to give some erasers to her pupils. If she gives each pupil 6 erasers, there will be 3 erasers left. If she gives each pupil 8 erasers, she will be short of 11 erasers. How many erasers does she have?
(Can you also share the concept of such question, thanks so much)
*uses algebraic concepts for normal sums*
6 units + 3 = 8 units - 11
2 units = 14
1 unit = 7
7 X 6 = 42
42 + 3 = 45 -
anonymus:
[/quote]Hi dharma,Dharma:
[quote=\"Almighty\"]
Let me put it in a simpler manner.
Pls see the highlighted 14 X 2 in your solution.The straight line of the shaded semicircle is 14 cm. Its the diameter of that semicircle also. Then y do u mulitply by 2? Please see highlighted portion of my solution on top.hope i am clear. Please dharma..dont get irritated..pls explain...
Very many thanks for yr continuous support...I'm still confused...As anonmus said
Its the diameter of THAT (shaded portion's )semicircle also..right.I understand yr first explanation ie., Perimeter of the shaded part
= Length of the 3 sides of a triangle + Curved length of the semicircle..but y can't i think like this???I treat the shaded portion as a seperate semi circle with its diameter 14 cm. Not the diameter of the big circle...
Anonmus..if u are clear with Dharma's explanation.please clarify to me toooooo... -
991narnia:
Eugene=> 1/3Pls help me with this question
1. Four children, Eugene, Fann, Grace and Herman, each have some stickers. The number of stickers that Eugene has is 1/2 of the total number of stickers that Fann, Grace, and Herman have. The number of stickers that Fann has is 1/4 of the total number of stickers that Eugene, Grace and Herman have. The number of stickers that Grace has is 2/3 of the total number of stickers that Eugene, Fann, and Herman have. If Herman has 47 stickers, how many stickers should Grace give to Fann so that Eugene and Fann have the same number of stickers?
Fann => 1/5
Grace => 2/5
Herman => 1 - 1/3 - 1/5 - 2/5 = 1/15
1/15 => 47
Eugene (5/15) => 5 x 47 = 235
Fann (3/15) => 3 x 47 = 141
No. of stickers Grace should give Fann
= 235 - 141
= 94 -
Almighty:
[/quote]Hi Almighty,anonymus:
[quote=\"Dharma\"]
Hi dharma,
Very many thanks for yr continuous support...I'm still confused...As anonmus said
Its the diameter of THAT (shaded portion's )semicircle also..right.I understand yr first explanation ie., Perimeter of the shaded part
= Length of the 3 sides of a triangle + Curved length of the semicircle..but y can't i think like this???I treat the shaded portion as a seperate semi circle with its diameter 14 cm. Not the diameter of the big circle...
Anonmus..if u are clear with Dharma's explanation.please clarify to me toooooo...
The side of the triangle (14cm) which touches the circle at 2 points and gives us one the shaded portion is NOT the diameter of the semicircle. The individual shaded portions are not separate and the question also does not suggest that. There is only 1 circle in this question.
The 3 curved lengths/arc are NOT semi-circles individually BUT together they form a semi circle.
Hope it is clearer now. -
Dharma:
[/quote]Almighty:
[quote=\"anonymus\"]
Thankyou very much Dharma..I now know why i should not think so. So grateful of u to be so patient in replying..
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Almighty:
[/quote]Dharma:
[quote=\"Almighty\"]
No prob. -
I have one speed qn which need help.
A lorry travelled at an average speed of 72km/h from Pink Town to Happy Town. 50 minutes later, a van started out from the same point towards the same destination at an average speed of 90km/h, reaching Happy Town at the same time.
a. How long did the van take to travel from Pink Town to Happy Town?
b. If both the lorry and the van arrived at Happy Town at 4.05pm at what time did the lorry start out??
Tx. -
Herbie:
I think that an important point to note is that the time taken by the van to overtake the lorry is the same as the time taken by the van to reach Happy TownI have one speed qn which need help.
A lorry travelled at an average speed of 72km/h from Pink Town to Happy Town. 50 minutes later, a van started out from the same point towards the same destination at an average speed of 90km/h, reaching Happy Town at the same time.
a. How long did the van take to travel from Pink Town to Happy Town?
b. If both the lorry and the van arrived at Happy Town at 4.05pm at what time did the lorry start out??
Tx.
Original Distance between 2 vehicles = 72 km/h x 5/6 h
= 60 km
Difference in speeds = 90 km/h - 72 km/h
= 18 km/h
Time van took to overtake lorry = Time van took to reach Happy Town
= 60 km / 18 km/h
= 3 1/3 h
Time lorry took to reach Happy Town = 3 1/3 h + 5/6 h
= 4 1/6 h
Time van started off -> 4 1/6 h before 4.05pm -> 11.55am
Hope this helps
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Herbie:
1. Calculate how much the lorry has travelled when the van first starts to move.I have one speed qn which need help.
A lorry travelled at an average speed of 72km/h from Pink Town to Happy Town. 50 minutes later, a van started out from the same point towards the same destination at an average speed of 90km/h, reaching Happy Town at the same time.
a. How long did the van take to travel from Pink Town to Happy Town?
b. If both the lorry and the van arrived at Happy Town at 4.05pm at what time did the lorry start out??
Tx.
Lorry
Speed = 72km/h
Time = 50min = 5/6h
Distance = 72km/h x 5/6h
= 60km
2. Determine the difference in speed between the 2 vehicles
Lorry = 72km/h
Van = 90km/h
Difference = 90km/h-72km/h
= 18km/h
3. Determine the time for the van to catch up on the lorry
Time taken for van to catch up on lorry = Time taken for van to complete its journey from Pink Town to Happy Town
The lorry was 60km ahead of the van when the van started its journey, and for every 1h, the van would have make up ground on the lorry by 18km,
Time = 60km/18km/h
= 3 1/3h (Ans for a)
4. Determine time taken for lorry to complete its journey
Time = 3 1/3h + 5/6h
= 4 1/6h
5. Determine time lorry starts its journey
Use timeline and deduct 4 1/6h from 4.05pm
Time started = 11.55am (Ans for b) -
Please clarify on the below speed problem.
Edmund drove Andrew from Jurong Point to Woodlands at a constant speed of 75 Km/h. Andrew rested for 20 mins before walking 3km home at a speed of 6km/h.Edmund took 15 minutes to return to Jurong Point to pick Ben up. HE then drove to Orchard at 75Km/h.The three people reached their destinations at the same time. What was the distance Edmund drove from Jurong Point to Orchard?
My method:
Time taken by Andrew to walk home from
Jurong point to Orchard = 65mins
6km ---- 1hr
3 km ----- ( 3/6 ) = 30min
30 + 20+ 15 = 65min
Speed of Edmund is 75km/hr
60 min ---- 75Km
65 min ----(65X75/60) = 81.25Km
Distance Edmund drove from Jurong Point to Orchard = 81.25 km (MY Answer)
Book Ansswer:
Total time taken by Andrew to reach home = 20+ 30 = 50 min (WHat happened to 15 mins?)
Time taken by Edmund to drive from jurog to Orchards = 50 -15 = 35 min
= 7/12h
Distance covered = 75 * 7/12 = 43.75km
Cannot understand marked in red.
Can anyone clarify??? :?
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