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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tisha
      last edited by

      Need help with this question:


      Susan takes 2 hrs to travel from Town A to Town B. Helen takes 3 hrs to travel from Town B to Town A. How long will it take for both Susan and Helen to meet along the way?

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      • ozoraO Offline
        ozora
        last edited by

        small:
        is_me_lblue:

        Hi,


        I am stuck again.

        Amos'salary is 20% more than Steve's but 20% less than Joe's. If their total salary is $2220,find Amos's salary.

        I always get the answer of 740 but answer given is 720.

        Thank you


        Hi,

        HTH..


        The key step is to calculate Joe's percentage. Given that Amos's salary is 20% less than Joe's.

        80% of Joe = 120% of Amos
        100% of Joe = 150% of Amos

        Steve = 100% (10 Units)
        Amos = 120% (12 Units)
        Joe = 150% (15 Units)

        37 Units = 2220
        1 Unit = 60
        12 Unit = 720

        or
        370% = 2220
        1% = 6
        120% = 720.

        šŸ˜Ž


        to anyone,
        can someone enlighten how 100% of Joe = 150% of Amos?
        I can't catch any clues on how to derive it.

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        • A Offline
          Apphia
          last edited by

          Fazillah, Linda and Winnie each owned a collection of comics. The total collection owned by Linda and Winnie was 3/2 as many comics as Fazillah owned. Linda owned 4/5 as many comics as the total collection owned by Fazillah and Winnie. If Winnie owned 169 fewer comics than Linda, how many comics must Fazillah and Linda each give to Winner in order for the three girls to have the same number of comics?


          Thank You.

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          • A Offline
            ADoc
            last edited by

            LaiHeng:
            small:

            [quote=\"is_me_lblue\"]Hi,


            I am stuck again.

            Amos'salary is 20% more than Steve's but 20% less than Joe's. If their total salary is $2220,find Amos's salary.

            I always get the answer of 740 but answer given is 720.

            Thank you


            Hi,

            HTH..


            The key step is to calculate Joe's percentage. Given that Amos's salary is 20% less than Joe's.

            80% of Joe = 120% of Amos
            100% of Joe = 150% of Amos

            Steve = 100% (10 Units)
            Amos = 120% (12 Units)
            Joe = 150% (15 Units)

            37 Units = 2220
            1 Unit = 60
            12 Unit = 720

            or
            370% = 2220
            1% = 6
            120% = 720.

            šŸ˜Ž


            to anyone,
            can someone enlighten how 100% of Joe = 150% of Amos?
            I can't catch any clues on how to derive it.[/quote]Hi, I believe there was a typo error in the answer above.
            It should be 100% of Joe = 150% of Steve instead of Amos.

            Hope this clarifies.
            cheers
            ADoc

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            • A Offline
              ADoc
              last edited by

              tisha:
              Need help with this question:


              Susan takes 2 hrs to travel from Town A to Town B. Helen takes 3 hrs to travel from Town B to Town A. How long will it take for both Susan and Helen to meet along the way?
              Hii! Hope this is useful.
              Key Concept: to understand net speed, i.e. 2 objects or persons moving at different speeds along the same distance but from opposite direction is equivalent to one single object/person covering the same distance but at a rate or a net (sum) speed of the original 2 objects/persons

              The same concept is applicable to questions concerning filling / draining water tanks.


              |--------- 1U ---------|
              [------------><--------]

              ------------->
              Susan's speed = Distance / Time = 1U / 2hr = (1/2)U per hr

              <--------
              Helen's speed = 1U / 3hr = (1/3)U per hr

              net speed or total speed = (1/2) + (1/3) = (5/6) U per hr
              this means that for every hr, the total distance covered by Susan & Helen = (5/6)U

              Hence, the time required to cover the entire distance AB = distance / total speed = 1U / (5/6)U = 1 x (6/5) = (6/5) hr = 1 & (1/5) hr

              Ans: It will take 1 & (1/5) hr for Susan & Helen to meet along the way.

              Check: In (6/5) hr, Susan will cover (6/5) divide by 2 = (3/5)U
              Helen will cover (6/5) divide by 3 = (2/5)U
              Total distance = 1U

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              • T Offline
                tisha
                last edited by

                Thank you ADoc for the solution.

                1 Reply Last reply Reply Quote 0
                • A Offline
                  ADoc
                  last edited by

                  Apphia:
                  Fazillah, Linda and Winnie each owned a collection of comics. The total collection owned by Linda and Winnie was 3/2 as many comics as Fazillah owned. Linda owned 4/5 as many comics as the total collection owned by Fazillah and Winnie. If Winnie owned 169 fewer comics than Linda, how many comics must Fazillah and Linda each give to Winner in order for the three girls to have the same number of comics?


                  Thank You.
                  Hi! Glad to help! My advice is to use the ratio method for efficiency. Model would give the same ans certainly but too cumbersome for this question in my opinion. Sorry if the solution looks lengthy. I just wanna be as clear as I can for each step of workings.

                  cheers!
                  ADoc

                  key concept: total collection of comics remains unchanged, hence convert the total ratio units to be equal

                  (L+W) : F = 3 : 2 (total = \"5\")
                  (F+W) : L = 5 : 4 (total = \"9\")

                  Since total collection of comics must be the same, therefore observing the above ratio units, student must be able to determine the common multiple or denominator = 5 x 9 = 45

                  (L+W) : F = 3 : 2 = (3 x 9) : (2 x 9) = 27 : 18 (total 45 units)
                  (F+W) : L = 5 : 4 = (5 x 5) : (4 x 5) = 25 : 20 (total 45 units)

                  Now we have:
                  F = 18U
                  L = 20U

                  L+W = 27U, therefore W = 27 - 20 = 7U or simply 45 - 18 - 20

                  How many comics = 1U?
                  since W has 169 fewer comics than L:
                  L - W = 20 - 7 = 13U = 169
                  1U = 169 / 13 = 13 comics

                  For each girl to have the same number of comics, it means each must have 45 / 3 = 15U

                  we can evaluate this in different ways, here's one:
                  F: 18U - 15U = 3U
                  3U = 3 x 13 = 39 comics

                  L: 20U - 15U = 5U
                  5U = 5 x 13 = 65 comics

                  ans: Fazillah & Winnie must give Linda 39 & 65 comics respectively in order for the three girls to have the same number of comics.

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                  • A Offline
                    ADoc
                    last edited by

                    tisha:
                    Thank you ADoc for the solution.

                    Hi Tisha! You're most welcome!
                    cheers!

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                    • ozoraO Offline
                      ozora
                      last edited by

                      have a question to ask ;

                      Jane bought 12 roses and 9 lilies for her mother. Each rose cost $2.50 less than each lily. If the total cost of the lilies was $0.50 more than the total cost of the roses, how much did Jane spend on the flowers altogther?

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                      • T Offline
                        tianzhu
                        last edited by

                        Emelyn:

                        Best wishes.
                        Oopss... sorry.... for not checking the earlier discussion.
                        Thanks for explaining it again.
                        Hi

                        You're welcome.

                        Best wishes

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