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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • H Offline
      Happygolucky
      last edited by

      HI Tianzhu,


      If I’m not wrong , one of the cubes at the uppermost layer was not in the question.

      Is the answer 2 cm?

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      • J Offline
        joyceling
        last edited by

        cubes for each level is (top to bottom ) 1,3,6

        water difference between top 2 levels and bottom level is the cubes difference: 8 cubes=1120-352x3=64, so each cube is 8 cm3
        so the height is 2cm

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        • T Offline
          tianzhu
          last edited by

          Happygolucky:
          HI Tianzhu,


          If I'm not wrong , one of the cubes at the uppermost layer was not in the question.

          Is the answer 2 cm?
          Hi

          This question is from http://www.misskoh.com
          Join the free membership to view the question from RGPS.
          I guess one of the cube is not in the question as it looks different from the others.

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          • T Offline
            tianzhu
            last edited by

            Perhaps girls of 2008/9 RGPS would like to comment on the extra cube shown in the picture.


            My gut feeling is it’s not there.

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            • D Offline
              Dharma
              last edited by

              tianzhu:
              Perhaps girls of 2008/9 RGPS would like to comment on the extra cube shown in the picture.


              My gut feeling is it's not there.
              You're right. It was hand-drawn (its the one at the top row - on the righthand side)

              Cube size - 2cm x 2cm x 2cm
              Height of container = 6cm

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              • D Offline
                Dharma
                last edited by

                tianzhu:
                Other than Guess and Check, what are the other alternatives to solve this problem?


                Annie wrote her mother's age followed by her own age to form a 4-digit number.She used the difference between their ages to subtract from the 4-digit number. Then Annie obtained the number 4489.What was Annie's age ? (RGPS P6 Prelim 2008 Q47)
                The 4 digit number is ABCD ... AB is mother's age while CD is Annie's age.

                ABCD - (AB - CD) = 4489

                ABCD = (AB00 + CD) -( AB - CD) = 4489

                AB - CD > 10 .... AB = 45

                4500 - CD - 45 + CD = 4489
                2CD = 34
                CD = 17

                Annie's age = 17

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                • T Offline
                  Tang
                  last edited by

                  Dharma:
                  Drdj:

                  Hi there,


                  Please help me with the following :

                  NanHua Prelim 2008

                  Qn 24
                  15 cats can catch 15 rats in 15 minutes. How long does it take 60 cats to cath 60 rats? [Ans = 15 mins - how do you know which qty to stay constant/change]

                  Thanks in advance πŸ™‚

                  15 cats - 15 rats - 15 mins
                  1 cat - 15 rats - 225 mins
                  1 cat - 60 rats - 900 mins
                  60 cats - 60 rats - 900/60 = 15 mins
                  (Only change 1 independent variable at a time)

                  15 cats 15 rats 15 min
                  1 cat 1 rat also 15 min
                  Hence 60 cats 60 rats also 15 min

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                  • T Offline
                    Tang
                    last edited by

                    Tang:
                    Dharma:

                    [quote=\"Drdj\"]Hi there,


                    Please help me with the following :

                    NanHua Prelim 2008

                    Qn 24
                    15 cats can catch 15 rats in 15 minutes. How long does it take 60 cats to cath 60 rats? [Ans = 15 mins - how do you know which qty to stay constant/change]

                    Thanks in advance πŸ™‚

                    15 cats - 15 rats - 15 mins
                    1 cat - 15 rats - 225 mins
                    1 cat - 60 rats - 900 mins
                    60 cats - 60 rats - 900/60 = 15 mins
                    (Only change 1 independent variable at a time)

                    15 cats 15 rats 15 min
                    1 cat 1 rat also 15 min
                    Hence 60 cats 60 rats also 15 min[/quote]15 cats 15 min

                    60 cats, the number of min will be less (Multiply by 15/60 - Original number of cats / New number of cats).
                    60 rats, the number of min will be more, since more rats to catch (Multiply by 60/15 - New number of rats / Original number of rats)

                    So 60 cats to catch 60 rats will require 15 x 15/60 x 60/15 = 15 min.

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                    • D Offline
                      Dharma
                      last edited by

                      Drdj:
                      Hi there,


                      Please help me with the following :

                      Misc
                      David paints once every 2 days. Larry paints once every 3 days.
                      If the 2 men met on 28th May, what is the earliest date David has to start work? [Answer = 24th May]

                      Thanks in advance πŸ™‚
                      The underlying assumption is both David and Larry met for the 1st time on 28 May.

                      If the assumption is not true, they would have met 6 days before i.e. on 22 May (LCM of 2 and 3)

                      Since the assumption holds, then the earliest David starts work is on 24 May (2 days after 22 May)

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                      • A Offline
                        Andaiz
                        last edited by

                        Drdj:
                        Hi there,


                        Please help me with the following :

                        Misc
                        David paints once every 2 days. Larry paints once every 3 days.
                        If the 2 men met on 28th May, what is the earliest date David has to start work? [Answer = 24th May]

                        Thanks in advance πŸ™‚
                        I would have assumed too that they've met for the first time on 28th May.
                        Larry would have worked on 28-3 i.e. 25th; and 25-3 i.e., 22nd.

                        With David painting every 2 days, he'd have worked 28th, 26th, or 24th or 22nd.

                        If they have never met previously, David's earliest date he could have started work is 24th.

                        We used to do the LCM way but now its modelling eh? I'd try with the number line


                        David 22_________ 24 _______26___________28
                        Larry 22_______________25_______________ 28

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