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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • T Offline
      Tang
      last edited by

      "Alfred, Ben and Chuck have some marbles. They have 21 marbles altogether. If Alfred gives Ben 2 marbles. Ben gives Chuck 3 marbles and Chuck gives Alfred 1 marbles, they will have equal numbers of marbles each. How many marbles does each of them have at first?"


      21 / 3 = 7

      Alfred – 7 - 1 + 2 = 8 marbles

      Ben – 7 + 3 - 2 = 8 marbles

      Chuck – 7 + 1 - 3 = 5 marbles


      Suggested solution by Tang’s sister

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      • T Offline
        Tang
        last edited by

        "Gregory and Timothy has 192 stickers together. After Timothy gave 30 stickers to Gregory, Timothy had thrice as many sticker as Gregory. How many stickers did Gregory have at first?"


        4u – 192
        1u – 192 / 4 = 48

        G – 48 - 30 = 18 stickers

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        • D Offline
          Daddy
          last edited by

          Thanks Devnahouse. I understood and going to teach my duaghter.

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          • Suz855S Offline
            Suz855
            last edited by

            //Moderator's note: Topics merged


            Hi,

            Not sure this qn should even be classify under P3 maths, anyway looking for a simplify soln, do share if you have good suggestion. No algebra or simultaneous equation, thanks

            Qn :
            There were 84 apples and pears in a box at first. When 2/5 of the apples
            and 2/3 of the pears were eaten, there were 40 fruits left.

            a) How many apples were there at first
            b) What fraction of the fruits left were pears?

            1 Reply Last reply Reply Quote 0
            • T Offline
              tutormum
              last edited by

              Just take the extra 2 balloons and add the 2 more she needs. That will be 4. If she gives 6 each at first, and 8 each later, that means she gives each student another 2 each. Since she have 4 balloons to give away, she has 2 students.

              Check: If she gives 2 students 6 balloons, she’ll have given 12, 2 X 6 = 12, there is 2 extra, therefore she has 14 balloons at first.
              If she gives 2 students 8 balloons, she’ll have to give 2 X 8 = 16. As she has only 14 balloons, she needs 2 more.
              Let me give another example.
              If Ken gives each child 10 sweets, he’ll have 3 left. If he gives each child 1 more, he needs another 5 sweets. How many children are there?
              Just take 3 + 5 = 8. If he gives each 1 more, he’ll give away all 8 sweets, right? So there are 8 children.
              Check: 8 X 10 = 80 + 3 = 83 sweets in total
              If he gives 1 more each, he needs 5 more, that is he needs 83 + 5 = 88. Since 1 child will be given 11, which is originally 10 + 1 more. 88/11 = 8.
              For this type of question, just add the extra and the required number and work from there.
              Hope my explanation is clear.

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              • T Offline
                tutormum
                last edited by

                Ooops. Sorry, forgot to quote. My early reply is for the following question.


                A teacher gave her students some balloons. If she gave 6 balloons to each student, she will have 2 balloons left. If she gave 8 balloons to each student, she will be short of 2 balloons. What is the smallest possible number of students she has?

                Try to do this without using ALGEBRA!

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                • T Offline
                  tutormum
                  last edited by

                  Suz855:
                  //Moderator's note: Topics merged


                  Hi,

                  Not sure this qn should even be classify under P3 maths, anyway looking for a simplify soln, do share if you have good suggestion. No algebra or simultaneous equation, thanks

                  Qn :
                  There were 84 apples and pears in a box at first. When 2/5 of the apples
                  and 2/3 of the pears were eaten, there were 40 fruits left.

                  a) How many apples were there at first
                  b) What fraction of the fruits left were pears?
                  Take 2 unit of apples + 2 unit of pears = 44 fruit eaten (84 - 40 = 44). Therefore 1 unit of apples + 1 unit of pears = 22 (44/2 sets)
                  Left 3 units of apples and 1 unit of pears = 40
                  As 1 unit of apples and 1 unit of pears = 22, 2 units of apples will be 40 - 22 = 18. Therefore 1 unit of apples = 18/2 = 9
                  Therefore, there are 9 X 5 units = 45 apples at first.
                  1 unit of pears will be 22 - 9 = 13. There are 13 X 3 = 39 pears at first.
                  Therefore fraction of fruits left were pears = 13/40.

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                  • T Offline
                    tutormum
                    last edited by

                    tianzhu:
                    Hi

                    Q2 touches on averages.
                    Is averages covered in P4 Maths?
                    Is in P5 syllabus.

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tutormum
                      last edited by

                      elkniwt:
                      watmekiasu:

                      Elkniwt


                      Hope this is correct -

                      1st - 3/8 + 3/8 = 6/8 = 3/4
                      2nd - 1/12 + 1/12 = 2/12 = 1/6
                      3rd - 1/3 + 1/6 = 3/6 = 1/3

                      so, the answer is 1/6

                      The ans given by the ans sheet is 2/9. I couldn't get it.

                      3/4 - 3/8 = 3/8, 3/8 +1/8 = 4/8 - 1/8 = 3/8
                      4/12 - 1/12 = 3/12, 3/12 + 1/3 = 7/12 - 6/12 = 1/12
                      3/9 - 1/9 = 2/9, 2/9 + 1/3 = 5/9 - 1/3 = 2/9

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        Tang
                        last edited by

                        tutormum:
                        Ooops. Sorry, forgot to quote. My early reply is for the following question.


                        A teacher gave her students some balloons. If she gave 6 balloons to each student, she will have 2 balloons left. If she gave 8 balloons to each student, she will be short of 2 balloons. What is the smallest possible number of students she has?

                        Try to do this without using ALGEBRA!
                        2 + 2 = 4

                        8 - 6 = 2

                        4 / 2 = 2 students


                        Or

                        Number of students 1 , 2
                        Multiple of 6 -- 6 , 12,
                        + 2 -- 8 , 14

                        Multiple of 8 -- 8 , 16
                        -2 -- 6 , 14

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