[quote]
equink posted: I've been trying to figure this out but I still don't understand.
Why is dx/dy proven to be 1/(dy/dx)? I know that dx/dy cannot be treated as a fraction because it simply isn't a fraction. Please help,thanks so much![/quote]@mathstuition88 answered:

Good question! A rigorous proof of that would require analysis (a math course in university), but one can prove it briefly using chain rule,

(dy/dx)(dx/dy)=dy/dy=1, hence dx/dy=1/(dy/dx).

Hope this helps!

Post and get your questions answered here: http://fbl.me/Tt

Hi violin_lover, this might be a little too late, but there's an initiative on Facebook going now which provides Pro Bono Maths Consultations. Just simply post your questions anonymously, and get answers on the same day!


Find it here at:

http://fbl.me/Ts

Hope this helps in your revision!

@sunnymoon, glad to help

[quote]Sunnymoon Wrote


Pls help this sum:

If a,b, c are positive integers such that (a + 1/(b+1/c)) = 37/16,
find the value of (a+b+c)[/quote]Hi Sunnymoon,

The answer is A = 2, B = 3, and C = 1/5

I really do not know how to upload photos through this editor. But the full working can be found on http://fbl.me/Tt

Hope this helps!

Hi parents,


I am starting this Facebook initiative which allows secondary students to post any maths problems and get solutions to their problems:

http://fbl.me/Ts

Do you find this initiative helpful? Just would like to gather any feedbacks & opinions you may have on this initiative?

Thank you!

Thanks!!

Mr Tan’s monthly savings (S) is directly proportional to the square root of his monthly income (I). His income in January and February 2011 is $3600 and $2500 respectively. His savings in January is $80 more than in February. Find the amount he saved in January 2011.