Tutor MathsGuru: Ask me for your burning Maths questions!

[singmathstutor]

Hi Almighty,


Edmund did not use 15min to alight Andrew, he used that time to get back to JP to fetch Ben. I think you have interpreted wrongly here.

[Almighty]

Thankyou singmathstutor…I got it!!!

[super star]

Hi Mathsguru

thanks for ur help.I have another problem pls help to solve this
Aurdrey & belle have some money each.If audrey spends $18 &belle spends $24 each day,audrey will still have $25 left when belle has spent all her money.If audrey spends $13 &bellespends $30each day,audrey will have $139 left when belle has spent all her money.How much money do they have altoghter?

mathsguru:

super star:

Maths guru
please help me in this problem.

Alan,Ben&charles had 864 trading cards.Ben won some of the cards from alan &as a result,ben's cards increased by 50%.charles then won some cards from ben & charles'cards increased by 40%.finally charles lost some of his cards to alan & alan's cards increased by 20%.In the end ,they realised that they each had an equal number of cards.how many cards did alan have at first?

Hi Super Star,

This question was posted quite some time back by another forum member. Here's my solution anyway...trick here is to work backwards systematically.

Cheers,
MathsGuru

http://www.postimage.org/image.php?v=gxHh7s0

[singmathstutor]

Almighty:

Thankyou singmathstutor..I got it!!!!

You're welcome, Almighty

[Daddy]

Hi


Need help on ratio question.

1) The ratio of the number of girls in 2A to the number of girls in 2B is 2:3.
The ratio of the number of boys in 2A to the number of boys in 2B is 5:3.
a) There are 5 more girls in 2B than 2A. Find the total number of girls in the 2 classes.
b) There are 6 more boys in 2A than 2B. Find the total enrolment of the pupils in the 2 classes.


2) Yvonne is 4 years older than Ken. The ratio of Yvonne’s age to Kenny’s age is 3:2. In how many years’ time will the ratio of Yvonne’s age to Kenny’s age be 9:7.

Thanks…

[Jolyn]

Hi


I have a question which needs your help:

1. 4 guavas and 5 managoes cost $12.50. A guava and a manago cost $3. Find the cost of 2 mangoes.

Thks

[singmathstutor]

Jolyn:

Hi


I have a question which needs your help:

1. 4 guavas and 5 managoes cost $12.50. A guava and a manago cost $3. Find the cost of 2 mangoes.

Thks

since a guava and a mango cost $3
4 guavas and 4 mangoes will cost $3 x 4 = $12
therefore since 4 guavas and 5 mangoes cost $12.50,
1 mango will cost $12.50-$12 = $0.50
2 mangoes cost $1

Hope this helps

[Dharma]

Daddy:

Hi


Need help on ratio question.

1) The ratio of the number of girls in 2A to the number of girls in 2B is 2:3.
The ratio of the number of boys in 2A to the number of boys in 2B is 5:3.
a) There are 5 more girls in 2B than 2A. Find the total number of girls in the 2 classes.
b) There are 6 more boys in 2A than 2B. Find the total enrolment of the pupils in the 2 classes.

a)\t3u – 2u = 1u = 5
No. of girls in the 2 classes = 5u = 5 x 5 = 25

b)\t5p – 3p = 2p = 6
1p = 3
Total enrolment = 5u + 8p = 25 + 8(3) = 49

Daddy:

2) Yvonne is 4 years older than Ken. The ratio of Yvonne's age to Kenny's age is 3:2. In how many years' time will the ratio of Yvonne's age to Kenny's age be 9:7.

Thanks..

3u – 2u = 1u = 4
Yvonne’s age now = 3 x 4 = 12
Kenny’s age now = 2 x 4 = 8

9p – 7p = 2p = 4
1p = 2

Yvonne’s age = 9 x 2 = 18

No of years taken for the ratio of Yvonne’s age to Kenny’s age be 9 : 7
= 18 – 12
= 6

[firebird]

Dear maths guru


Good morning.

Please help me on this question:

Harry and Sally were at a party. Harry shook hands with 4 times as many boys as girls while Sally shook hands with 5 times as many boys as girls.
How many boys and how many girls were there at the party?

Thank you.
Firebird

[Dharma]

firebird:

Dear maths guru


Good morning.

Please help me on this question:

Harry and Sally were at a party. Harry shook hands with 4 times as many boys as girls while Sally shook hands with 5 times as many boys as girls.
How many boys and how many girls were there at the party?

Thank you.
Firebird

http://www.postimage.org/image.php?v=Pqr9HmJ