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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • F Offline
      fxchow
      last edited by

      small:
      Hi fxchow,


      HTH but I am not so sure on my answer for part (b).

      a)
      Given that 30% of the pupils in Sch A is 45 more than 40% of the pupils in Sch B.
      0.3A - 45 = 0.4B --> x10

      3A = 4B + 450 ----- equation (1)


      If 10% of the pupils in Sch A leaves to join Sch B, there will be 200 more pupils in Sch A than Sch B
      0.9A – 200 = 0.1A + 1B
      0.8A = 1B + 200 --> x10

      8A = 10B + 2000 ----- equation (2)


      We will need to eliminate A to get B;

      equation (1) x 8:
      24A = 32B + 3600

      equation (2) x 3:
      24A = 30B + 6000

      32B + 3600 = 30B + 6000
      2B – 6000 – 3600
      2B = 2400
      1B = 1200

      There are 1200 pupils in Sch B


      b)
      from equation (1) :

      3A = 4 X 1200 + 450
      3A = 4800 + 450
      3A = 5250
      1A = 1750 (100%)

      The different between School A and School B is:
      1750 – 1200 = 550

      1750 = 100%
      550 = 550/1750 x 100%
      = 1100 / 35 %
      = 31 3/7%


      There are 31 3/7% percent less pupils in Sch B than Sch A
      Hi Small,

      Thank you for your solution, your answer b is correct. 😄

      1 Reply Last reply Reply Quote 0
      • F Offline
        fxchow
        last edited by

        MathIzzzFun:
        fxchow:

        Hi,


        Can someone help in this question from Raffles Girls'Prm Sch-Prelim-Q18. TIA 😄

        There are more pupils in Sch A than Sch B.
        30% of the pupils in Sch A is 45 more than 40% of the pupils in Sch B.
        If 10% of the pupils in Sch A leaves to join Sch B, there will be 200 more pupils in Sch A than Sch B.

        a) How many pupils are there in Sch B?
        b) How many percent less pupils are there in Sch B than Sch A?
        Leave your answer as fraction in the simplest form.

        hi fxchow,

        hope this helps 😄

        http://www.flickr.com/photos/62167097@N02/5842021695/in/photostream

        cheers.


        Hi MathIzzzFun,

        Thank you for your model drawing, it's great. 😄

        fxchow

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          fxchow:
          MathIzzzFun:

          [quote=\"fxchow\"]Hi,


          Can someone help in this question from Raffles Girls'Prm Sch-Prelim-Q18. TIA 😄

          There are more pupils in Sch A than Sch B.
          30% of the pupils in Sch A is 45 more than 40% of the pupils in Sch B.
          If 10% of the pupils in Sch A leaves to join Sch B, there will be 200 more pupils in Sch A than Sch B.

          a) How many pupils are there in Sch B?
          b) How many percent less pupils are there in Sch B than Sch A?
          Leave your answer as fraction in the simplest form.

          hi fxchow,

          hope this helps 😄

          http://www.flickr.com/photos/62167097@N02/5842021695/in/photostream

          cheers.


          Hi MathIzzzFun,

          Thank you for your model drawing, it's great. 😄

          fxchow[/quote]u r welcome 😄

          cheers.

          1 Reply Last reply Reply Quote 0
          • ozoraO Offline
            ozora
            last edited by

            ksi:
            http://i54.tinypic.com/xprbkl.jpg\">

            thanks KSi

            1 Reply Last reply Reply Quote 0
            • corneyAmberC Offline
              corneyAmber
              last edited by

              you are welcome ozora. 🙂

              1 Reply Last reply Reply Quote 0
              • S Offline
                stary
                last edited by

                Hi all,


                Have 2 questions that I need help with…

                1.
                A and B start cycling at the same time from the same place.
                If they cycle in the opposite direction, they will be 37 2/5 km apart after 55 min.
                If they cycle in the same direction, A will be 2 1/5 km ahead of B after 55 min.
                (a) Find the diff. in their average speed.
                (b) Find the average speed of the slower cyclist.(Express in decimals)

                2.
                At 2pm, Melvin started from Vivo City and travelled towards Sun City at an average speed of 78km/h. At 3:12pm, he went past Andrew who was travelling from Sun City to Vivo City. At 3:42pm, the distance between Melvin and Andrew was 75 km.
                (a) What was Andrew’s speed?
                (b) At what time did Andrew reach Vivi City?


                Your help is GREATLY appreciated by me.

                Best regards,
                Stary

                1 Reply Last reply Reply Quote 0
                • R Offline
                  raghupavithra
                  last edited by

                  Mr Hambali is 39 years 4 months old.his son is 1/3 as old as he.How old is his son?

                  (Give your answer in years)

                  how to do this sum

                  1 Reply Last reply Reply Quote 0
                  • R Offline
                    raghupavithra
                    last edited by

                    Mr sim earns $2500 every month.After giving 3/5 of his salary to his wife and 1/2 of the remainder to his son, he saves the rest. How much money can Mr sim save in 3 years?

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      bobsg01
                      last edited by

                      Primary 6 Problem.


                      Thanks for your kind help.

                      http://i53.tinypic.com/2vceyvk.jpg\">

                      1 Reply Last reply Reply Quote 0
                      • corneyAmberC Offline
                        corneyAmber
                        last edited by

                        raghupavithra:
                        Mr Hambali is 39 years 4 months old.his son is 1/3 as old as he.How old is his son?

                        (Give your answer in years)

                        how to do this sum
                        Father's age in months = 468+4 = 472
                        Son age = 1/3 *472 = 472/3 in months
                        Son's age in years
                        = 472/(3*12) = 13 1/9 years

                        1 Reply Last reply Reply Quote 0

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