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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • T Offline
      tianzhu
      last edited by

      concerned1970:

      Hi Tianzhu! Seriously, I've great difficulty in understanding in solving this sum.
      How to tell the difference of chicken wings is dropped by 7 for every increase of a girl? How did you get 120 and why was it divided by 7? Ty! 😄
      Hi

      Please have another look at the example given in the link and follow same steps for your question.

      Assume there were 30 boys and each boy ate 4 chicken wings, you’ll have (30*4) or 120 chicken wings.

      Next consider an increase of 1 girl, so for 29 boys and 1 girl, you’ll have a difference of (29*4) - 3 or 113 chicken wings.

      For an increase of 1 girl the difference is (120-113) or 7 chicken wings.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • D Offline
        Donnie
        last edited by

        thanks.

        1 Reply Last reply Reply Quote 0
        • S Offline
          sianonehalf
          last edited by

          Need help!! A farmer has 80 chickens and goats. There are 250 legs. How many chickens are there? (Use assuming all method). Anyone??

          1 Reply Last reply Reply Quote 0
          • corneyAmberC Offline
            corneyAmber
            last edited by

            sianonehalf:
            Need help!! A farmer has 80 chickens and goats. There are 250 legs. How many chickens are there? (Use assuming all method). Anyone??

            Assume all 80 chickens.
            80x2 = 160
            250-160 = 90
            4-2 = 2 (goat has 4 legs but chickens have 2 legs)

            90/2 = 45 -> no. of goats.

            Hence chickens is (80-45)=35.

            By ksi junior

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            • A Offline
              applepie
              last edited by

              Need help on this question please…


              The total mass of 5 packets of flour and 4 packets of rice is 490 kg. Each packet of flour has a mass twice that of a packet of rice. What is the mass of each packet of flour ?

              Thanks.

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                applepie:
                Need help on this question please...


                The total mass of 5 packets of flour and 4 packets of rice is 490 kg. Each packet of flour has a mass twice that of a packet of rice. What is the mass of each packet of flour ?

                Thanks.
                Hi

                One way to solve it.

                Rice ----- 1 unit
                Flour ----- 2 units

                Mass for 5 packets of flour ------ (5*2) ------ 10 units
                Mass for 4 packets of rice ----- 4 units

                14 units ----- 490
                1 unit ----- 35

                2 units ----- 70 (the mass of each packet of flour)

                Best wishes

                1 Reply Last reply Reply Quote 0
                • corneyAmberC Offline
                  corneyAmber
                  last edited by

                  applepie:
                  Need help on this question please...


                  The total mass of 5 packets of flour and 4 packets of rice is 490 kg. Each packet of flour has a mass twice that of a packet of rice. What is the mass of each packet of flour ?

                  Thanks.
                  Let u be the mass of rice.
                  mass of flour is 2u.
                  5(2u) + 4(u) -> 490
                  14 u-> 490
                  u-> 35
                  2u -> 70
                  Mass of each packet of flour is 70kg

                  By ksi junior

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                  • A Offline
                    applepie
                    last edited by

                    Got it, thanks tian zhu and ksi…!

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      concerned1970
                      last edited by

                      Hi, pls help to solve with a model diagram if possible. Ty!


                      1) Fatimah has 40 coins. Some of the coins are 50-cent coins and the rest are
                      20-cent coins. The total value is $16.10 How many 50-cent coins does Fatimah
                      have?

                      2) In a long jump competition, Paul jumped 0.16m further than Royston while
                      Shawn jumped 0.24m less than Paul. If the total distance jumped by the three
                      boys was 3.44m, how far did each boy jump?

                      1 Reply Last reply Reply Quote 0
                      • corneyAmberC Offline
                        corneyAmber
                        last edited by

                        concerned1970:
                        Hi, pls help to solve with a model diagram if possible. Ty!


                        1) Fatimah has 40 coins. Some of the coins are 50-cent coins and the rest are 20-cent coins. The total value is $16.10 How many 50-cent coins does Fatimah have?

                        2) In a long jump competition, Paul jumped 0.16m further than Royston while Shawn jumped 0.24m less than Paul. If the total distance jumped by the three boys was 3.44m, how far did each boy jump?

                        1. Assume all 40 are 20-cent coins.
                        40 x 0.20 = 8
                        16.10-8.00 = 8.10
                        0.50 - 0.20 = 0.30

                        8.10/0.30 = 27

                        There are 27 50-cent coins.

                        Check: 27 x 0.50 = 13.50, 13x0.20 = 2.60 Total = 13.50+2.60 = 16.10

                        2.

                        P (__u___)(16)
                        R (__u___)
                        S (__u+16-24)

                        u+16 + u + u+16-24 -> 344
                        3u = 336
                        u = 112

                        Paul jumped (112+16)= 128 cm= 1.28m
                        Royston jumped 112cm = 1.12m
                        Shawn jumped 112-8 = 104cm = 1.04m


                        by ksi junior

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