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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • S Offline
      speedmaths.012624com
      last edited by

      kamom:
      Help :please:


      http://img.photobucket.com/albums/v606/shirleywoon/SH-Sep2011/MathOlympiadTest1e.jpg\">

      THANKS A MILLION
      http://i44.tinypic.com/w8173p.jpg\">

      Hi kamom,

      The answer is 55 degrees.

      Please see diagram.

      First, draw a square, say 1 cm by 1 cm.
      Next, draw an isosceles triangle on the right, and use trigonometry to find the value of lengths a, b and c.
      Then draw another isosceles triangle on the left, and use trigonometry to find the value of lengths d, e and f.

      g = c - e

      w + x = 70 degrees

      tan (w + 70 degrees) = (f + 1 + b) / g

      x = (70 degrees - w) = 55 degrees.

      The solution I used involves trigonometry, which is normally beyond P6 pupils.

      May I know the source of this question?

      Cheers


      Speedmaths.com
      http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=43&t=25433&start=10


      .

      1 Reply Last reply Reply Quote 0
      • T Offline
        thinkgmama
        last edited by

        Thank you do much. I finally understand. 🙂

        1 Reply Last reply Reply Quote 0
        • H Offline
          homeworkmummy
          last edited by

          tianzhu:
          homeworkmummy:


          Could you pls advise if this can be solved by model method. My DD was confused with the percentage method.

          Hi

          It’s possible to provide graphical representations of the information in the question.

          Perhaps you may want to check with your DD.

          What is confusing her?

          What is her understanding of percentages after reading her textbooks?

          What is her understanding on comparing two quantities of percentages?

          Percentages is first started in P5 Maths.Maybe, she is confused because her teacher has not covered the topic in Percentages for her P6 syllabus yet.

          Best wishes

          Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            homeworkmummy:

            Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?
            Hi

            Good Morning.

            You're welcome.

            “Finding percentage increase/decrease” is only covered in P6 syllabus.

            http://www.moe.gov.sg/education/syllabuses/sciences/files/maths-primary-2007.pdf

            Best wishes

            1 Reply Last reply Reply Quote 0
            • H Offline
              homeworkmummy
              last edited by

              tianzhu:
              homeworkmummy:


              Thanks tianzhu. She is not familiar with the comparison method. Is this only cover in p6?

              Hi

              Good Morning.

              You're welcome.

              “Finding percentage increase/decrease” is only covered in P6 syllabus.

              http://www.moe.gov.sg/education/syllabuses/sciences/files/maths-primary-2007.pdf

              Best wishes

              Thanks Tianzhu for the info.

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              • T Offline
                tianzhu
                last edited by

                homeworkmummy:

                Thanks Tianzhu for the info.
                Hi

                You’re welcome.

                I believe she’ll understand it better when the teacher has covered the topic.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • C Offline
                  Chan09
                  last edited by

                  I do need help as I can solve using algebra but even looking at models this is tough:

                  a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                  a) how many people were there altogether? ans: 31 people
                  b) were there more boys than girls and how many more? ans: 19 more girls than boys

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Chan09:
                    I do need help as I can solve using algebra but even looking at models this is tough:

                    a group of friends play tennis. each of them play with everyone else. Ann played with 4 times as many girls as boys. Bob played with 5 times as many girls as boys.
                    a) how many people were there altogether? ans: 31 people
                    b) were there more boys than girls and how many more? ans: 19 more girls than boys
                    Hi

                    Ann played with 4 times as many girls as boys, so
                    Girls : Boys --> 4u +1 : 1u,
                    total 5u + 1 people and there were 3u + 1 more girls

                    Bob played with 5 times as many girls as boys,
                    Girls : Boys --> 4u + 1 : 1u -1 = 5 : 1

                    cross multiply or equalize --> 4u + 1 = 5u -5
                    1u --> 6
                    5u + 1 = 31
                    3u+1 --> 19

                    There were 31 people and there were 19 more girls than boys.

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • H Offline
                      hazelwong
                      last edited by

                      Hi, I came across this type of question:

                      Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
                      The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
                      TIA 😄

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        hazelwong:
                        Hi, I came across this type of question:

                        Charlie had $490 more than Eugene. Charlie spent 1/7 of his money, Eugene spent 1/5 of his money. If Eugene spent $20 less than Charlie, find the total amount of money the children had in the end.
                        The answer given is such a complex model (subdivided into many units) :? that I wonder if there is an easier way?
                        TIA 😄
                        Hi

                        Eugene's money --> 5 units
                        Eugene spent --> 1 unit
                        Charlie spent --> 1 unit + 20
                        Charlie's money --> 7 x (1 unit + 20) = 7 units + 140
                        So, 7 units + 140 = 5 units + 490
                        1 unit --> 175
                        ...you should be able to complete the solution from here 😄

                        cheers.

                        1 Reply Last reply Reply Quote 0

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