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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • N Offline
      nounou
      last edited by

      deleted

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      • N Offline
        nounou
        last edited by

        Hi, need help on another Q. Kindly help. Thank you.


        Evaluate 2012^2 - 2011^2 + 2010^2 - 2009^2 + ...
        + 4^2 - 3^2 + 2^2 - 1^2

        :? :?:

        :thankyou:

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        • K Offline
          koguma
          last edited by

          deleted

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          • K Offline
            koguma
            last edited by

            nounou:
            Hi, need help on another Q. Kindly help. Thank you.


            Evaluate (2012^2 - 2011^2) + (2010^2 - 2009^2) + ...
            + (4^2 - 3^2) + (2^2 - 1^2)

            :? :?:

            :thankyou:
            Use this formulae : a^2 āˆ’ b^2 = (a + b)(a āˆ’ b)

            2012^2 - 2011^2
            = (2012+2011)(2012-2011)
            = 2012+2011

            2010^2 - 2009^2
            = (2010+2009)(2010-2009)
            = 2010+2009

            4^2 - 3^2
            = (4+3)(4-3)
            = 4+3

            2^2 - 1^2
            = (2+1)(2-1)
            = (2+1)

            so you need to add 1+2+3+4 .... +2009+2010+2011+2012 to get the ans.

            hopefully someone else can give a shorter working answer.

            1 Reply Last reply Reply Quote 0
            • N Offline
              nounou
              last edited by

              deleted šŸ•ŗ

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              • N Offline
                nounou
                last edited by

                Hi, thank you very much for your help. I understand your workings.


                Q: how to find 1+2+3+4 .... +2009+2010+2011+2012 ???? :?:

                Please help. :thankyou: :lovesite:

                koguma:
                nounou:

                Hi, need help on another Q. Kindly help. Thank you.

                Evaluate (2012^2 - 2011^2) + (2010^2 - 2009^2) + ...
                + (4^2 - 3^2) + (2^2 - 1^2)

                :? :?:

                :thankyou:

                Use this formulae : a^2 āˆ’ b^2 = (a + b)(a āˆ’ b)

                2012^2 - 2011^2
                = (2012+2011)(2012-2011)
                = 2012+2011

                2010^2 - 2009^2
                = (2010+2009)(2010-2009)
                = 2010+2009

                4^2 - 3^2
                = (4+3)(4-3)
                = 4+3

                2^2 - 1^2
                = (2+1)(2-1)
                = (2+1)

                so you need to add 1+2+3+4 .... +2009+2010+2011+2012 to get the ans.

                hopefully someone else can give a shorter working answer.

                1 Reply Last reply Reply Quote 0
                • J Offline
                  Jtutor
                  last edited by

                  Hi nounou,


                  To solve for 1+2+3+…+2010+2011+2012, you can group them together as follow:
                  (1+2012)+(2+2011)+(3+2010)+…
                  There will be a total of 2012/2=1006 pairs.
                  Hence 1006 x 2013 = 2,025,078.

                  Hope it helps.

                  Cheers,
                  Jtutor

                  1 Reply Last reply Reply Quote 0
                  • N Offline
                    nounou
                    last edited by

                    :thankyou: :udaman: :lovesite:

                    Jtutor:
                    Hi nounou,

                    To solve for 1+2+3+..............+2010+2011+2012, you can group them together as follow:
                    (1+2012)+(2+2011)+(3+2010)+...
                    There will be a total of 2012/2=1006 pairs.
                    Hence 1006 x 2013 = 2,025,078.

                    Hope it helps.

                    Cheers,
                    Jtutor

                    1 Reply Last reply Reply Quote 0
                    • Y Offline
                      Yamong
                      last edited by

                      Can anyone recommend physics tution arround bukit timah?

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                      • H Offline
                        htn
                        last edited by

                        Hi


                        Please help.

                        Secondary Two Maths.

                        Factorise

                        1)2r^2-5r-3

                        Expand and simplify the following expressions
                        1)(a+b)^2 - (a-b)^2

                        2)(x+2y)(x-6y)- (x-3y)(x-y)

                        TIA

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