Q&A - P5 Math

[Jamesbond]

Ben sold 1295 chickens and ducks at the market yesterday. The ratio of the number of chickens sold to the number of ducks sold was 4:3. Today, he sold another 685 chickens and ducks. As a result, the ratio of the number of chickens sold to the number of ducks sold for the two days was 2:1. How many chickens did he sell on the second day?

[PapayaDad]

yesterday = 7u

7u=1295
u=185
chicken to duck 4u:3u is 740:555

today = 685

both days = 1295 + 685 = 1980
both days = 3p = 1980
p=660
both days ratio is 2p:1p…1320:660

Yesterday chicken = 740
Both days total chicken = 1320
Today chicken = 1320 - 740=580

check
Today duck = 685 - 580 = 105

Yesterday 740:555
Today 580:105
Both days 1320:630…correct

[Jamesbond]

PapayaDad:

yesterday = 7u

7u=1295
u=185
chicken to duck 4u:3u is 740:555

today = 685

both days = 1295 + 685 = 1980
both days = 3p = 1980
p=660
both days ratio is 2p:1p....1320:660

Yesterday chicken = 740
Both days total chicken = 1320
Today chicken = 1320 - 740=580

check
Today duck = 685 - 580 = 105

Yesterday 740:555
Today 580:105
Both days 1320:630...correct

:thankyou: Papayadad.

[Jamesbond]

Dan had some 50 cent coins and 20 cent coins in the ratio 4:5. He exchanged six 50 cent for 20 cent coins. The ratio of the number of 50 cent coins to the number of 20 cent coins Dan has becomes 1:5. What is the total sum of money that Dan has?

[PapayaDad]

Exchange six 50 cents for fifteen 20 cents


At first 4u:5u
Change -6:+15
End 1p:5p

4u-6…1p
5u+15…5p

Make the part the same

20u-30…5p
5u+15…5p

20u-30=5u+15
15u=45
u=3

At first 4u:5u
At first 12:15
12 fifty cents = 6 dollars
15 twenty cents = 3 dollars
Total : 9 dollars

Check:
At first 12:15
change -6:+15
End 6:30 = 1:5 correct
6 fifty cents = 3 dollars
30 twenty cents = 6 dollars
total : 9 dollars…correct

[Gold]

Hi, this is LS, Heyhoe's son! This is the first time using my own account! I'm so excited!!! :imcool:

Can u please help me with these?
1: In the figure, the length of the smaller square is 16cm and the length of the bigger square is 23cm. Find the shaded area.
Photo will be uploaded in the next msg.
2: this figure is made up of 2 squares and a right angled triangle. Find the shaded area. Thanks :clubmyself: the photos are more than 640 pixels wide. I'll try again.

[Gold]

:sad: If you have, it's the 5A textbook area of triangle pg 115 Q5 and Q6, challenging practice B.

I really can't upload the photo... :sad: :sad:

[tianzhu]

Gold:

:sad: If you have, it's the 5A textbook area of triangle pg 115 Q5 and Q6, challenging practice B.

I really can't upload the photo... :sad: :sad:

Hi

You may insert an image by following these steps:

1) Do a print screen of the portion you want to upload.

2) Edit using Paint. Cut out the portion of the question you want to upload.

3) Save file in pictures

4) Go to Flickr (Free sign up as member) or other storage sites. Upload file. Select medium size. Right click to copy URL of image.

5) Coming back to Kiasuparents forum, click insert image button.

Best wishes

[carol73]

The Queen, prince and princess had 270 diamonds. After receiving 90 diamonds for her birthday, the Queen decided to give 1/2 of the diamonds to the prince, the prince than gave 2/5 of his diamonds to the princess.in the end the three of them had the same number of diamonds, how many diamonds did each of them have at first

[chloecube]

carol73:

The Queen, prince and princess had 270 diamonds. After receiving 90 diamonds for her birthday, the Queen decided to give 1/2 of the diamonds to the prince, the prince than gave 2/5 of his diamonds to the princess.in the end the three of them had the same number of diamonds, how many diamonds did each of them have at first

270 + 90 = 360

now -
Queen - 3 units
Prince - 3 units
princess - 3 units

work backwards
before -
Queen - 6 units
Prince - 2 units
princess - 1 unit

9u - 360
1u - 40

so Queen - 240 - 90 = 150
Prince - 80
princess - 40