Tutor MathsGuru: Ask me for your burning Maths questions!

[Dharma]

kwcllf:

Please help with the following question:


Amanda has 3 times as much money as Jolie. Colonel has $27 more than Amanda. The amount of money Jolie has is $1274 less than 5 times the amount of money Amanda has. Find the amount of money Jolie and Colonel have altogether.

Thanks!

Amanda : 3u
Jolie : 1u
Colonel : 3u + $27

1u = 5(3u) - $1274
14u = $1274
1u = $91

Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $391

[kwcllf]

Hi Dharma,


Thanks so much…really appreciate the help.

[tisha]

Dharma:

1u = $91


Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $455

Isn't 4 x 91 +27 = 391 ?

[Dharma]

tisha:

Dharma:

1u = $91


Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $455

Isn't 4 x 91 +27 = 391 ?

Silly me ...thanks Tisha

[SaPan]

Dear uncles/aunties,


pls help me with this question.

At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi’s notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end?

[iFruit]

SaPan:

Dear uncles/aunties,


pls help me with this question.

At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi's notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end?

At first assume Kumar has = 2n notes
Then Devi has = 3n notes

$80 = $2 x 40 = $5 x 16. So Devi lost 40 notes and kumar gained 16 notes

so new ratio = 3n-40: 2n+16 = 11:10

10(3n-40) = 11(2n+16)----> 30n -400 = 22n + 176 ---> 8n = 576-->n = 72

So Devi at the end = 3n-40 = 72x3 - 40 = 176

HTH.

[SaPan]

iFruit:

SaPan:

Dear uncles/aunties,


pls help me with this question.

At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi's notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end?

At first assume Kumar has = 2n notes
Then Devi has = 3n notes

$80 = $2 x 40 = $5 x 16. So Devi lost 40 notes and kumar gained 16 notes

so new ratio = 3n-40: 2n+16 = 11:10

10(3n-40) = 11(2n+16)----> 30n -400 = 22n + 176 ---> 8n = 576-->n = 72

So Devi at the end = 3n-40 = 72x3 - 40 = 176

HTH.

thank you so much ifruit!
again, you made it look so easy. :lol:

[tinkfirst]

Can anyone help on this pattern?


2, 5, 12, 20, _, 42, _.

Thanks

[Dharma]

tinkfirst:

Can anyone help on this pattern?


2, 5, 12, 20, _, 42, _.

Thanks

Hi tinkfirst,

Can you pls check whether the 2nd term is 5 or 6? Thanks

[tianzhu]

Dharma:

Can you pls check whether the 2nd term is 5 or 6?

Hi Dharma

I think it's 6.

The likely sequence is 2,6,12,20,30,42,56

Best wishes