Tutor MathsGuru: Ask me for your burning Maths questions!
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is_me_lblue:
Additional amt needed to buy all 85 magnetsHi,
Pls assist below question. The answer given in the answer sheet is 16r but I feel a bit not right (hope I am wrong).
\"Leroy had only $9 and he needed to buy 85 magnets. His father gave him another $r. The magnets were sold in pack of 5 for $r. How much more money did he need to pay for all the 85 magnets ?\"
I need to explain to my son but I wonder what happen to the $9 if the answer is 16r.
Thnks
= $(85/5 x r) - $(9 + r)
= $(17r - 9 - r)
= $(16r - 9)
Think the given answer is incorrect -
Dharma:
Additional amt needed to buy all 85 magnetsis_me_lblue:
Hi,
Pls assist below question. The answer given in the answer sheet is 16r but I feel a bit not right (hope I am wrong).
\"Leroy had only $9 and he needed to buy 85 magnets. His father gave him another $r. The magnets were sold in pack of 5 for $r. How much more money did he need to pay for all the 85 magnets ?\"
I need to explain to my son but I wonder what happen to the $9 if the answer is 16r.
Thnks
= $(85/5 x r) - $(9 + r)
= $(17r - 9 - r)
= $(16r - 9)
Think the given answer is incorrect
Thank you very much. Finally I can explain to my son with the correct answer.
-
Please help with the following question:
Amanda has 3 times as much money as Jolie. Colonel has $27 more than Amanda. The amount of money Jolie has is $1274 less than 5 times the amount of money Amanda has. Find the amount of money Jolie and Colonel have altogether.
Thanks! -
kwcllf:
Amanda : 3uPlease help with the following question:
Amanda has 3 times as much money as Jolie. Colonel has $27 more than Amanda. The amount of money Jolie has is $1274 less than 5 times the amount of money Amanda has. Find the amount of money Jolie and Colonel have altogether.
Thanks!
Jolie : 1u
Colonel : 3u + $27
1u = 5(3u) - $1274
14u = $1274
1u = $91
Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $391 -
Hi Dharma,
Thanks so much…really appreciate the help. -
Dharma:
Isn't 4 x 91 +27 = 391 ?1u = $91
Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $455 -
tisha:
Silly me ...thanks Tisha
Isn't 4 x 91 +27 = 391 ?Dharma:
1u = $91
Amt of money Jolie & Colonel have altogether
= 4u + $27
= 4($91) + $27
= $455 -
Dear uncles/aunties,
pls help me with this question.
At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi’s notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end? -
SaPan:
At first assume Kumar has = 2n notesDear uncles/aunties,
pls help me with this question.
At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi's notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end?
Then Devi has = 3n notes
$80 = $2 x 40 = $5 x 16. So Devi lost 40 notes and kumar gained 16 notes
so new ratio = 3n-40: 2n+16 = 11:10
10(3n-40) = 11(2n+16)----> 30n -400 = 22n + 176 ---> 8n = 576-->n = 72
So Devi at the end = 3n-40 = 72x3 - 40 = 176
HTH. -
iFruit:
thank you so much ifruit!
At first assume Kumar has = 2n notesSaPan:
Dear uncles/aunties,
pls help me with this question.
At first, Kumar has only $5 notes and Devi had only $2 notes.
The number of notes Kumar had is 2/3 of Devi's notes.
When Devi gave Kumar $80, he changed all the $80 to $5 notes.
Then the number of notes Devi has now is 1/10 more than Kumar.
How many notes does Devi have at the end?
Then Devi has = 3n notes
$80 = $2 x 40 = $5 x 16. So Devi lost 40 notes and kumar gained 16 notes
so new ratio = 3n-40: 2n+16 = 11:10
10(3n-40) = 11(2n+16)----> 30n -400 = 22n + 176 ---> 8n = 576-->n = 72
So Devi at the end = 3n-40 = 72x3 - 40 = 176
HTH.
again, you made it look so easy. :lol:
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