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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • A Offline
      ADoc
      last edited by

      vannessa:
      Thank you ADoC

      Hi Vannessa! hope it was useful. cheers!

      1 Reply Last reply Reply Quote 0
      • Y Offline
        Yu Xuan
        last edited by

        Bunny27:
        Hi,

        In the 1st week of a fund raising campaign, class 6a raised 4 times as much as class 6b. In the 2nd week, 6a raised another $240 while 6b raised another $160. Given that 6a raised thrice as much as 6b within these 2 weeks, what was the total amount of money raised by the 2 classes?
        Hi

        First week;
        6a --> 4 units
        6b --> 1 unit

        2 weeks;
        6a --> 4 units + $240 = 3 parts

        6b -->1 unit + $160 = 1 part
        ------> 3 units + 480 = 3 parts

        Using a model;

        6a [ ][ ][ ][ ][--$240--]
        6b [ ][ ][ ][----$480---]

        Hence ;
        1unit --> $480 - $240 = $240
        5units --> $240 * 5 = $1200

        $1200 + $240 + $160 = $1600

        1 Reply Last reply Reply Quote 0
        • A Offline
          ADoc
          last edited by

          Apphia:
          Yes, models will be a great help. It will be easier for me to explain to my daughter.


          Warm Rgds, Apphia
          Hi Apphia! sorry for the delay.

          cheers!
          ADoc
          http://postimage.org/image/2bao708o4/

          http://postimage.org/image/2bari2xno/

          http://postimage.org/image/2bat5ma5g/

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          • Y Offline
            yeonee
            last edited by

            Need Help!


            The sum of Ben’s age and his younger brother’s age is 26. The product of their ages is 144.
            What is Ben’s age in 20 years’ time?

            1 Reply Last reply Reply Quote 0
            • B Offline
              Bunny27
              last edited by

              Thanks again, Yu Xuan!


              Yu Xuan:
              Bunny27:

              Hi,
              In the 1st week of a fund raising campaign, class 6a raised 4 times as much as class 6b. In the 2nd week, 6a raised another $240 while 6b raised another $160. Given that 6a raised thrice as much as 6b within these 2 weeks, what was the total amount of money raised by the 2 classes?

              Hi

              First week;
              6a --> 4 units
              6b --> 1 unit

              2 weeks;
              6a --> 4 units + $240 = 3 parts

              6b -->1 unit + $160 = 1 part
              ------> 3 units + 480 = 3 parts

              Using a model;

              6a [ ][ ][ ][ ][--$240--]
              6b [ ][ ][ ][----$480---]

              Hence ;
              1unit --> $480 - $240 = $240
              5units --> $240 * 5 = $1200

              $1200 + $240 + $160 = $1600

              1 Reply Last reply Reply Quote 0
              • D Offline
                Dharma
                last edited by

                yeonee:
                Need Help!


                The sum of Ben's age and his younger brother's age is 26. The product of their ages is 144.
                What is Ben's age in 20 years' time?
                144 = ( 2 x 2 x 2 ) x ( 2 x 3 x 3 ) = 8 x 18
                Ben’s age now = 18
                Ben’s younger brother’s age = 8
                Ben’s age in 20 years’ time = 18 + 20 = 38

                1 Reply Last reply Reply Quote 0
                • ozoraO Offline
                  ozora
                  last edited by

                  Need help again

                  1. Tom had 2 boxes, A and B, containing an equal number of white beads. He divided the white beads in BoxA into groups of 60 and to each group, he added 4 red beads before stringing them up to make necklances.

                  He divided the white beads in BoxB into groups of 90 and to each group, he added 5 blue beads before stringing them up to make necklances.
                  When he had finished, there was no more white beads in either boxes and he had used 28 more red beads than blue beads. How many red beads did he use altogther?

                  2. Jane and Shelia shared a sum of money.
                  If Jane gave 1/4 of her share to Shelia, Shelia would have $400 more than Jane
                  If Jane gave 1/5 of her share to Shelia, Shelia would have $154 more than Jane.
                  How much money did they have altogther?

                  3.A total of 350 children joined Camp A and CampB. Camp A was for girls and Camp B was for boys. THere were 2/5 as many girls as boys. More children joined in. For every 2 additional girls joined in Camp A, 1 additional boy joined CampB. Thus after the 1st day, there was an equal number of boys and girls. How many additional boys joined Camp B?

                  1 Reply Last reply Reply Quote 0
                  • R Offline
                    rossypolly
                    last edited by

                    hi there! Pls help me with this qn


                    Sam bought some vanilla cookies and gave 1/2 of them to Mike.
                    Mike bought some chocholate bars and gave 1/2 of them to Sam.
                    Sam ate 8 chocolate bars and Mike ate 16 vanilla cookies.
                    The ratio of Sam’s vanilla cookies to chocolate bars became 8:1 and the ratio of Mike’s vanilla cookies to chocolate bars became 3:1.

                    How many vanilla cookies did Sam buy?

                    (Really appreciate your help)

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      trytry
                      last edited by

                      LaiHeng:
                      Need help again

                      1. Tom had 2 boxes, A and B, containing an equal number of white beads. He divided the white beads in BoxA into groups of 60 and to each group, he added 4 red beads before stringing them up to make necklances.

                      He divided the white beads in BoxB into groups of 90 and to each group, he added 5 blue beads before stringing them up to make necklances.
                      When he had finished, there was no more white beads in either boxes and he had used 28 more red beads than blue beads. How many red beads did he use altogther?
                      BOX-----------------------------..........................--A.......................B
                      no of white bead in each gp.........................60......................90
                      Ratio of white beads in each gp....................2........................3
                      Ratio of no of gp.........................................3........................2
                      Ratio of additional beads in each box.........3x4=12..............2x5=10
                      ....................................................................6.....................5


                      Difference of 6units-5units=1unit---------------------28

                      Number of red beads used=6x28=168

                      BTW LaiHeng, where did you get the question from?

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        trytry
                        last edited by

                        LaiHeng:
                        2. Jane and Shelia shared a sum of money.

                        If Jane gave 1/4 of her share to Shelia, Shelia would have $400 more than Jane
                        If Jane gave 1/5 of her share to Shelia, Shelia would have $154 more than Jane.
                        How much money did they have altogther?

                        ?
                        After condition 1.
                        Jane has.....................[....][....][....]
                        Shelia has...................[....][....][....]{400}

                        Reinstate condition before condition 1,
                        ie Shelia returned 1/4 of jane's to her.
                        .................................-------------20u-------
                        Jane...........................[||||][||||][||||][||||]
                        Shelia.........................[||||][||||]{400}
                        ..................................----10u.....

                        Now condition 2.
                        ..................................-------16u--------154
                        Jane...........................[||||][||||][||||][]==
                        Shelia.........................[||||][||||][|||]{400}
                        ..................................-------14u-----

                        ..................................................2 u-------->400-154=246
                        ..................................................1u--------->246/2=123

                        They have................20u+10u+400=30u+400=30x123+400
                        .....................................=4090




                        [/img]

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