Tutor MathsGuru: Ask me for your burning Maths questions!
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Mrs Tan bought 4 times as many toy guns as teddy bears. She spent $1750 altogether. A toy gun cost $10 less than a teddy bear. The total cost of toy guns is $490 more than the cost of teddy bears.
a) how much did Mrs Tan spend on the teddy bears?
b) how much did one teddy bear cost? -
Jcong:
Hi ,Mrs Tan bought 4 times as many toy guns as teddy bears. She spent $1750 altogether. A toy gun cost $10 less than a teddy bear. The total cost of toy guns is $490 more than the cost of teddy bears.
a) how much did Mrs Tan spend on the teddy bears?
b) how much did one teddy bear cost?
Answer is on page 339 .
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&start=3380 -
Grateful thanks to Uncle Dharma, jieheng, MathIzzzFun + others for spending your precious time plus effort in providing worked solutions so that it helps my younger sister in her SMOPS 2011’s preparation.
Here’s one from the APMOPS 2005 Q5 as she will be taking part in APMOPS 2011. No Answer is given. Pls help to provide worked solution and thanks in advance.
Five classes A,B,C,D and E took part in an international chess competition.
Each class sent in 2 participants.
The rules of the competition were:
(a) Participants do not compete with each other for more than 1 game,
(b) Participants from the same class cannot compete with each other.
After a few rounds of competitions, it turned out that all had completed different number of games, except for a participant from class A.
How many games had the 2 participants from class A completed? -
Another 2 questions from APMOPS - Not sure from which year.
Q1
There were 4 cards labeled with letters M, A, T and H respectively. A single-digit number is written at the back of each card. They are then placed side by side, as shown below, so that a four-digit number is obtained. Peter discovered that regardless of the number written behind the \"A\" card, the difference between the four-digit number and hundred times of the sum of its digits is always 4212.
Find the numbers written behind the cards labeled M, T and H respectively.
Note: Picture showing 4 identical boxes placed side by side with M, A, T and H labeled on each box.
Q2
Given that S=1+11+111+1111+...+ 111...1 (100 of 1's)
find the sum of the digits of S.
Answers given
Q1: M=5, T=1 and H=2
Q2: 415 -
Chan09:
Q1)Need some help
1) 3/5 are $50. 2/3 of the remainder are $10 and $5 notes and the rest are $2 notes. He had twenty four $2 notes. The number of $10 notes is 1/7 of the number of $5 notes. What is the number of $10 notes he has?
Ans: 4
2) the ratio of the number of Chinese pupils to the number of Malay pupils was 10:7. The ratio of the number of Malay boys to Malay girls was 9:5. What was the rato of the number of Malay girls to the number of chinese pupils in it's simplest form?
Ans: 1:2
Thank you :?
[--][--][--][--][--][--][--][--][--][--][--][--][--][--][--] (total 15u)
[--] denotes $50
[--] denotes $10 & $5
[--] denotes $2
the reason for using 15u is because of 3/5 are $50. 2/3 of the remainder are $10 and $5 notes
from the model ,
2u -----> 24 (He had twenty four $2 notes)
1u -----> 12
4u -----> 48
total number of ($10 & $5) notes = 48
Ratio of $10 : $5 = 1 : 7
the number of $10 notes is 1/8 of the total number of ($10 & $5) notes = (1/8) * 48 = 6 (Ans)
Q2)
Malay boys 9u
Malay girls 5u
total Malay pupils = 9u + 5u = 14u
Chinese pupils 10u
Malay pupils 7u
Need to change the Malay pupils from 7u -----> 14u for easy comparison
Chinese pupils 10u*2 -----> 20u
Malay pupils 7u*2 -----> 14u
the rato of the number of Malay girls to the number of chinese pupils in it's simplest form = 5u : 20u = 1 : 4 (Ans) -
Vanilla Cake:
M*1000+A*100+T*10+H - 100*(M+A+T+H) = 4212Another 2 questions from APMOPS - Not sure from which year.
Q1
There were 4 cards labeled with letters M, A, T and H respectively. A single-digit number is written at the back of each card. They are then placed side by side, as shown below, so that a four-digit number is obtained. Peter discovered that regardless of the number written behind the \"A\" card, the difference between the four-digit number and hundred times of the sum of its digits is always 4212.
Find the numbers written behind the cards labeled M, T and H respectively.
Note: Picture showing 4 identical boxes placed side by side with M, A, T and H labeled on each box.
Answers given
Q1: M=5, T=1 and H=2
M*1000+T*10+H - 100*(M+T+H) = 4212
=> H = 2 , T = 1
M*1000+10+2 - 100*(M+1+2) = 4212
M*1000-M*100 = 4500
=> M = 5 -
Pls help to provide worked solutions and thanks in advance.
Answer given: m=1
http://postimage.org/image/2uvidl31g/ -
Pls help to provide worked solutions and thanks in advance.
No answer given
http://postimage.org/image/2uwahpzfo/ -
Pls help to provide worked solutions and thanks in advance.
No answer given.
But I think the answer is 38.7 cm2
http://postimage.org/image/enqfh0tg/ -
Vanilla Cake:
hiPls help to provide worked solutions and thanks in advance.
No answer given.
But I think the answer is 38.7 cm2
http://postimage.org/image/enqfh0tg/
http://postimage.org/image/2vdnmv63o/
cheers.
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