Q&A - P3 Math
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//Moderator's note: Topics merged.
Hi,
I have one difficult question to ask. Please help. Thank.
\"Alfred, Ben and Chuck have some marbles. They have 21 marbles altogether. If Alfred gives Ben 2 marbles. Ben gives Chuck 3 marbles and Chuck gives Alfred 1 marbles, they will have equal numbers of marbles each. How many marbles does each of them have at first?\" :?
Thanks
daddy -
Let me try…
Alfred + 1
Ben + 2
Chuck + 3
Total number is still 21
21 - 1 - 2 - 3 = 15 / 3 = 5 each. -
Thanks,
But seem not correct. After they have given the marbles. All have equal amount of marbles. How?? -
Sorry. I interpret the question wrongly.
This shld be a "Work Backward" method. \t\t\t\t\t\t\t
3 of them have equal share of 21, must be 7 marble each for Alfred, Ben and Chuck.\t\t\t\t\t\t\t
\t\t\t\t\t\t
1) Add back what they have at first:\t\t\t
2) Then minus off what they receive from each other
Alfred
7 + 2(gives to Ben) - 1 (receives from Chuck) = 8
Ben :
7 + 3 (gives to Chuck) - 2 (receives from Alfred) = 8
Chuck :
7 + 1 (gives to Alfred) - 3 (receives from Ben) = 5
\t\t\t\t
\t
Now check again,\t\t\t\t\t\t\t
Alfred has 8 at first, gives away 2 to Ben and receives 1 from Chuck = 7
Ben has 8 at first, gives away 3 to Chuck, and receives 2 from Alfred, = 7
Chuck has 5 at first, receives 3 from Ben, and gives away 1 to Alfred = 7
Hope is correct now. -
elkniwt:
Hi elkniwt,Hi,
I was going thr' this paper with my P3 girl. Need help in this qn. Thanks
Catholic High 2007 CA2 Q40.
http://www.postimage.org/image.php?v=Ts2ds4FJ
You have 5 boxes, (top, bottom, left, right and middle)
The unknown is the middle one in the 3rd diagram. For patterns you need to find the relationship of the numbers of 4 outer boxes and the number in the middle box. You need to manipulate the numbers using the 4 basic operations and see if you get the number in the middle box for the 1st and 2nd diagrams. If they are correct, then you have established the pattern and go get the middle number in the 3rd diagram.
1st diagram
Left box + Top box = 1/8 + ¾ = 7/8
Right box + Bottom box = 3/8 + 1/8 = 4/8
Middle box = 7/8 – 4/8 = 3/8
2nd diagram
Left box + Top box = 1/3 + 1/6 = 4/12 + 2/12 = 6/12
Right box + Bottom box = 4/12 + 1/12 = 5/12
Middle box = 6/12 – 5/12 = 1/12
3rd diagram
Left box + Top box = 1/3 + 1/3 = 3/9 + 3/9 = 6/9
Right box + Bottom box = 3/9 + 1/9 = 4/9
Middle box = 6/9 – 4/9 = 2/9 -
Daddy:
http://www.postimage.org///Moderator's note: Topics merged.
Hi,
I have one difficult question to ask. Please help. Thank.
\"Alfred, Ben and Chuck have some marbles. They have 21 marbles altogether. If Alfred gives Ben 2 marbles. Ben gives Chuck 3 marbles and Chuck gives Alfred 1 marbles, they will have equal numbers of marbles each. How many marbles does each of them have at first?\" :?
Thanks
daddy -
"Alfred, Ben and Chuck have some marbles. They have 21 marbles altogether. If Alfred gives Ben 2 marbles. Ben gives Chuck 3 marbles and Chuck gives Alfred 1 marbles, they will have equal numbers of marbles each. How many marbles does each of them have at first?"
21 / 3 = 7
Alfred – 7 - 1 + 2 = 8 marbles
Ben – 7 + 3 - 2 = 8 marbles
Chuck – 7 + 1 - 3 = 5 marbles
Suggested solution by Tang’s sister -
"Gregory and Timothy has 192 stickers together. After Timothy gave 30 stickers to Gregory, Timothy had thrice as many sticker as Gregory. How many stickers did Gregory have at first?"
4u – 192
1u – 192 / 4 = 48
G – 48 - 30 = 18 stickers -
Thanks Devnahouse. I understood and going to teach my duaghter.
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//Moderator's note: Topics merged
Hi,
Not sure this qn should even be classify under P3 maths, anyway looking for a simplify soln, do share if you have good suggestion. No algebra or simultaneous equation, thanks
Qn :
There were 84 apples and pears in a box at first. When 2/5 of the apples
and 2/3 of the pears were eaten, there were 40 fruits left.
a) How many apples were there at first
b) What fraction of the fruits left were pears?
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