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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      kwcllf:
      MathIzzzFun:

      [quote=\"kwcllf\"]Hi Please help with the following question:


      There are some marbles. They are used to make a square with 13 rows and 13 columns. The marbles are then rearranged to form 2 squares, with the smaller square having 7 marbles less than the bigger square in each row. How many marbles are there in each row for the 2 squares?

      Thanks.

      Hi
      This will involve solving of quadratic equations which are taught in Sec.

      For upper primary, use Guess and Check, you will get 5 per row for small square and 12 per row for big square (13 x 13 = 5 x 5 + 12 x 12)

      cheers.

      Hi,

      I am a little confused. My kid was also told to use Guess & Check.

      But if marbles are used to make 13 rows and 13 columns, aren't there 14 marbles needed across each rows and columns to construct the square grid? That is, there are 14x14=196 marbles in total if we use the marbles to mark each point on the square grid.

      The question said there are 7 marbles more in each row for the bigger sqaure. It didn't say there are 7 rows more :?[/quote]Hi

      hope this will help ..

      http://i44.tinypic.com/15chrp4.jpg\">

      cheers.

      1 Reply Last reply Reply Quote 0
      • H Offline
        helenLim2011
        last edited by

        Hello, I have a burning Question Here. Hope you can solve. Thanks Mr Kiasu


        Can Someone help me at this Maths Problem? Its driving me NUTS

        Jim and Fred had a total of $40. Jim gave 3/7 of his money to Fred. Fred then gave 1/6 of the total amount of money he had to Jim. In the end, each of them had the same amount of money. How much money did each of them have at first?

        (This is a P5 Question so plse reply in a P5 manner of understanding!) Bless you for helping me out…

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          helenLim2011:
          Hello, I have a burning Question Here. Hope you can solve. Thanks Mr Kiasu


          Can Someone help me at this Maths Problem? Its driving me NUTS

          Jim and Fred had a total of $40. Jim gave 3/7 of his money to Fred. Fred then gave 1/6 of the total amount of money he had to Jim. In the end, each of them had the same amount of money. How much money did each of them have at first?

          (This is a P5 Question so plse reply in a P5 manner of understanding!) Bless you for helping me out...
          Hi

          you can work backwards ..
          In the end,
          Jim --> $ 20
          Fred --> $20 --- this is after Fred gave 1/6 to Jim, so this amount is equal to 5/6 of Fred's money.

          Before Fred gave 1/6 to Jim,
          Fred --> $ 20 x 6 /5= $ 24
          Jim --> $ 40-$ 24 = $16 -- this is equal to 4/7 of Jim's money at first

          At first,
          Jim --> $ 16 x 7/4 = $ 28
          Fred --> $ 40 - $ 28 = $ 12

          cheers.

          1 Reply Last reply Reply Quote 0
          • H Offline
            helenLim2011
            last edited by

            Hi MathIzzzFun


            Thanks for the great help but my girl is the visual sort. Are you able to illustrate the answer using models?


            Much thanks again!

            1 Reply Last reply Reply Quote 0
            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              helenLim2011:
              Hi MathIzzzFun


              Thanks for the great help but my girl is the visual sort. Are you able to illustrate the answer using models?


              Much thanks again!
              Hi

              I do not have time to draw the model at the moment, I will try to put in words here..

              in the end,
              Jim --> $ 20
              Fred --> $20 --- this is after Fred gave 1/6 to Jim, so this amount is equal to 5/6 of Fred's money
              -- draw 5 blocks for Fred (since 5/6 left) and also 5 blocks for Jim since they have the same amount... ie end state :
              Jim --> 5 blocks
              Fred --> 5 blocks

              from here, one can see that this is after Fred give 1/6 to Jim, so, 5 blocks represent 5/6 of Fred's money before the transfer, ie he transferred 1 block to Jim. So, draw the model before this transfer --> transfer 1 block back to Fred and you will have 6 blocks for Fred and 4 blocks for Jim .. so, before Fred give 1/6 to Jim
              Jim --> 4 blocks
              Fred --> 6 blocks

              again, from this model, one can see that Jim had 4 blocks left after giving 3/7 to Fred ie the 4 blocks represent 4/7 of Jim which means that before the transfer, Jim had 7 blocks. Now, draw the final model which is the start state -->
              transfer 3 blocks back to Jim and we have
              Jim --> 7 blocks
              Fred --> 3 blocks...
              10 blocks --> $ 40
              1 block --> $4

              At first,
              Jim --> $4 x 7 = $ 28
              Fred --> $4 x 3 = $ 12

              cheers.

              1 Reply Last reply Reply Quote 0
              • H Offline
                helenLim2011
                last edited by

                MathIzzzFun You are indeed a math wizard.


                Thanks very much and have a great time coaching online.

                A very pleased Mdm Lim:)

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  helenLim2011:
                  MathIzzzFun You are indeed a math wizard.


                  Thanks very much and have a great time coaching online.

                  A very pleased Mdm Lim:)
                  u r welcome 😄

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • K Offline
                    Kafer
                    last edited by

                    Hi i have one qn


                    John speed is ia x m/s.
                    Mary speed is y m/s
                    If john starts 2 sec later, he will take 8 secs to catch up with mary.
                    If john starts to run only when mary is 8m ahea 5 sec to catch up with her.
                    Form two eqn in x an y.

                    Can help?

                    1 Reply Last reply Reply Quote 0
                    • V Offline
                      violin_lover
                      last edited by

                      8x=10y and 8+5y=5x

                      1 Reply Last reply Reply Quote 0
                      • K Offline
                        Kafer
                        last edited by

                        violin_lover:
                        8x=10y and 8+5y=5x

                        Thanks! Can exlain how you workput the eqn?

                        1 Reply Last reply Reply Quote 0

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