Q&A - P5 Math

[tianzhu]

Gold:

:sad: If you have, it's the 5A textbook area of triangle pg 115 Q5 and Q6, challenging practice B.

I really can't upload the photo... :sad: :sad:

Hi

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Best wishes

[carol73]

The Queen, prince and princess had 270 diamonds. After receiving 90 diamonds for her birthday, the Queen decided to give 1/2 of the diamonds to the prince, the prince than gave 2/5 of his diamonds to the princess.in the end the three of them had the same number of diamonds, how many diamonds did each of them have at first

[chloecube]

carol73:

The Queen, prince and princess had 270 diamonds. After receiving 90 diamonds for her birthday, the Queen decided to give 1/2 of the diamonds to the prince, the prince than gave 2/5 of his diamonds to the princess.in the end the three of them had the same number of diamonds, how many diamonds did each of them have at first

270 + 90 = 360

now -
Queen - 3 units
Prince - 3 units
princess - 3 units

work backwards
before -
Queen - 6 units
Prince - 2 units
princess - 1 unit

9u - 360
1u - 40

so Queen - 240 - 90 = 150
Prince - 80
princess - 40

[carol73]

hi


how do you determine that now is 3units
thanks

chloecube:

carol73:

The Queen, prince and princess had 270 diamonds. After receiving 90 diamonds for her birthday, the Queen decided to give 1/2 of the diamonds to the prince, the prince than gave 2/5 of his diamonds to the princess.in the end the three of them had the same number of diamonds, how many diamonds did each of them have at first

270 + 90 = 360

now -
Queen - 3 units
Prince - 3 units
princess - 3 units

work backwards
before -
Queen - 6 units
Prince - 2 units
princess - 1 unit

9u - 360
1u - 40

so Queen - 240 - 90 = 150
Prince - 80
princess - 40

[PapayaDad]

270 + 90 = 360


so:

Q = 120
P = 120
Ps = 120

work backward

Q at first have = 120 x 2 - 90 = 150
Q gave P : (150+90)/2 =120

P (after giving 2/5p) =120
So before giving 2/5 ; P=200
So P at first have 200-120=80

Ps at first have 270-150-80= 40

[lego]

Can someone please help me with this question.


There were some sweets in Boxes A, B and C.
Box A contained 1/7 of the total number of sweets in Boxes B and C.
The ratio of the number of sweets in Box B to the total number of sweets in Boxes A and C is 3:1
If there are 30 more sweets in Box B than Box A, find the total number of sweets in Boxes A, B and C.

[PapayaDad]

Total=8u


B+C=7u
A=u

B=6u
A+C=2u

B-A=6u-u=5u=30
u=6
Total=8u=48

[lego]

PapayaDad:

Total=8u


B+C=7u
A=u

B=6u
A+C=2u

B-A=6u-u=5u=30
u=6
Total=8u=48

Thank you so much!

[Shimmer]

Hi


Can someone help me on these two question ?

1. Daniel has $160 more than Raja. If Daniel gives Raja 1/10 of his money, he will have 3 times as much money as Raja.
A) How much money does Raja have at first ?
B) Express Raja’s money as a fraction of Daniel’s money.

2. There were 240 people in a shopping centre. 3/5 of them were men. Some men then left the shopping centre. The number of men in the shopping centre was 4/7 of the remaining people. How many men left the shopping centre ?

[tianzhu]

Shimmer:

Hi

Can someone help me on these two question ?
1. Daniel has $160 more than Raja. If Daniel gives Raja 1/10 of his money, he will have 3 times as much money as Raja.
A) How much money does Raja have at first ?
B) Express Raja's money as a fraction of Daniel's money.

Hi

You may use MD or work with units.

Before
Daniel ------ 10 units + 160
Raja ------ 10 units

AfterDaniel ------ 9 units + 144
Raja ------ 11 units + 16

11 units + 16
(x3)
33 units + 48

33 units + 48 --------- 9 units + 144

24 units ------ 96
1 unit ------- 4

Raja ------ 10 units -------10*4 ------ 40

Daniel ------ 10 units + 160 ------- 200

Raja's money as a fraction of Daniel's money ------ 40/200 ------1/5

Best wishes