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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • Suz855S Offline
      Suz855
      last edited by

      Dear Amberzbon


      1) Ann spent $5850 on some bags and wallets. She bought 5 times as many bags as wallets. She paid $4400 more for bags than wallets. Each bag cost $60 more than a wallet. Find the cost of one wallet.

      b [ ][ ][ ][ ][ ] + difference ** (b + w = 5850)
      w [ ]

      4u + difference = 4400
      6u + difference = 5850, 2u = 5850 - 4400 = 1450
      1u = 725

      4u (bag) + difference = 4400
      difference = 4400 - (4x725) = 1500

      no. of bags = 1500 divide 60 = 25
      therefore, no. of wallets –> 25 divide 5 = 5

      5 wallets cost $725, 1 wallet therefore cost $145

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      • V Offline
        Vanilla Cake
        last edited by

        amberzbon:
        2)Eileen gets $2 more allowance than Mabel each week. Each girl spends $21 per week and saves the rest. When Eileen saves $72, Mabel only saves $48. How much allowance does Mabel get each week?
        If Eileen get $2 more allowance than Mabel each week, Eileen's weekly saving will be more than Mabel's weekly saving by $2.

        E: [Spent=$21][Saving][$2]
        M: [Spent=$21][Saving]

        Difference in total savings
        $72-$48 = $24

        Eileen saves $2 more in 1 week and to save $24 more, it will take 24/2 = 12 weeks.

        To save $48, Mabel will also need 12 weeks.
        In 1 week, Mabel saves $48/12 = $4

        Weekly allowance for Mabel = Spent+saving = $(21+4) = $25

        Submitted by VC's mum

        1 Reply Last reply Reply Quote 0
        • W Offline
          wahwah
          last edited by

          Can someone help me with the following P3 Math problem sum? Many thanks in advance.


          Bob has thrice as many buttons as Ali. Ali has 179 buttons lesser then Carlos. Carlos has 228 buttons more than Ali and Bob. How many buttons do the three boys have altogether?

          1 Reply Last reply Reply Quote 0
          • D Offline
            Dharma
            last edited by

            wahwah:
            Can someone help me with the following P3 Math problem sum? Many thanks in advance.


            Bob has thrice as many buttons as Ali. Ali has 179 buttons lesser then Carlos. Carlos has 228 buttons more than Ali and Bob. How many buttons do the three boys have altogether?
            Hi,

            Think there's something wrong with your Qn. How can Carlos have 179 buttons more than Ali when the next sentence says that Carlos has 228 more buttons than Ali and Bob?

            1 Reply Last reply Reply Quote 0
            • M Offline
              Muffins
              last edited by

              wahwah:
              Can someone help me with the following P3 Math problem sum? Many thanks in advance.


              Bob has thrice as many buttons as Ali. Ali has 179 buttons lesser then Carlos. Carlos has 228 buttons more than Ali and Bob. How many buttons do the three boys have altogether?
              Hi wahwah, I think the question is a little wrong as, when I try to work it out, I keep getting thhat 1 unit is equal to 4 units + 48. Could you please get back to us on this? Thanks!

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              • W Offline
                wahwah
                last edited by

                Hi Muffins and Dharma,

                Thanks for trying out the question. That was the question on my son’s holiday assignment paper. Will have to wait for the new term to verify with the teacher. Will update again.

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                • M Offline
                  Muffins
                  last edited by

                  wahwah:
                  Hi Muffins and Dharma,

                  Thanks for trying out the question. That was the question on my son's holiday assignment paper. Will have to wait for the new term to verify with the teacher. Will update again.
                  Thanks for the heads-up wahwah! πŸ™‚

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                  • D Offline
                    Devnahouse
                    last edited by

                    Hello,

                    Can help me solve this one.

                    The cost of 7 erasers and 3 rulers is $5.05.
                    The cost of 2 erasers and 6 rulers is $3.95
                    Find the cost of 2 erasers and 2 rules.

                    Many thanks.

                    1 Reply Last reply Reply Quote 0
                    • corneyAmberC Offline
                      corneyAmber
                      last edited by

                      The cost of 7 erasers and 3 rulers is $5.05.

                      The cost of 2 erasers and 6 rulers is $3.95
                      Find the cost of 2 erasers and 2 rules.

                      7 erasers + 3 rulers = 5.05 --------(1) x 2
                      14 erasers + 6 rulers = 10.1 --------(2)
                      2 erasers + 6 rulers = 3.95 ---------(3)

                      (2)-(3),
                      12 erasers = 6.15
                      2 erasers = 1.025
                      Then 6 rulers = 3.95-1.025 = 2.925
                      2 rulers = 0.975

                      So 2 erasers + 2 rulers = 1.025 + 0.975 = $2

                      or (1) + (2)
                      9 erasers + 9 rulers = $9
                      2 erasers + 2 rulers = $2 (proportionately)

                      1 Reply Last reply Reply Quote 0
                      • D Offline
                        Devnahouse
                        last edited by

                        ksi:
                        The cost of 7 erasers and 3 rulers is $5.05.

                        The cost of 2 erasers and 6 rulers is $3.95
                        Find the cost of 2 erasers and 2 rules.

                        7 erasers + 3 rulers = 5.05 --------(1) x 2
                        14 erasers + 6 rulers = 10.1 --------(2)
                        2 erasers + 6 rulers = 3.95 ---------(3)

                        (2)-(3),
                        12 erasers = 6.15
                        2 erasers = 1.025
                        Then 6 rulers = 3.95-1.025 = 2.925
                        2 rulers = 0.975

                        So 2 erasers + 2 rulers = 1.025 + 0.975 = $2

                        or (1) + (2)
                        9 erasers + 9 rulers = $9
                        2 erasers + 2 rulers = $2 (proportionately)
                        Thanks ksi. But I do not how to explain this simultaneous equation to a P3

                        My initial solution is :
                        7 Erasers + 3 Rulers = $5.05
                        2 Erasers + 6 Rulers = $ 3.95

                        Add them together we have
                        9 Erasers + 9 Rulers = $5.05 + 3.95 = $9

                        Each set of 1 Eraser 1 Ruler = $1
                        Therefore 2 sets of Eraser & Ruler = $2.

                        I'm thinking since the question ask for the price of 2 sets, the working out of each price is not necessary.

                        Anyone to shed some lights? Thanks in advance.

                        1 Reply Last reply Reply Quote 0

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