Q&A - P3 Math

[Dharma]

Devnahouse:

Hello,

Can help me solve this one.

The cost of 7 erasers and 3 rulers is $5.05.
The cost of 2 erasers and 6 rulers is $3.95
Find the cost of 2 erasers and 2 rules.

Many thanks.

http://www.postimage.org/image.php?v=TsKNGfA

[Devnahouse]

Dharma, Thanks for taking time to explain in model form. Thanks ksi for your further clarifications. Appreciated.

[buds]

Easiest method to solve this one?


A snail climbed 1cm up a wall in Day 1,
2cm in Day 2, 3cm in Day 3 and so on..

Each day, it climbed 1cm more than it did
the previous day. How many days did the
snail take to climb 21cm?

[Dharma]

buds:

Easiest method to solve this one?


A snail climbed 1cm up a wall in Day 1,
2cm in Day 2, 3cm in Day 3 and so on..

Each day, it climbed 1cm more than it did
the previous day. How many days did the
snail take to climb 21cm?

Hi Buds

Easiest way is by listing

Day 1 => 1
Day 2 => 1 + 2 = 3
Day 3 => 1 + 2 + 3 = 6
Day 4 => 1 + 2 + 3 + 4 = 10
Day 5 => 1 + 2 + 3 + 4 + 5 = 15
Day 6 => 1 + 2 + 3 + 4 + 5 + 6 = 21

The snail took 6 days to climb 21cm

But if we have a large number, eg number of days taken by the snail to climb 210cm; using listing method will be very time consuming.

We need to establish a pattern

This is a question a series of consecutive numbers starting from 1

1 + 2 + 3 + ….+ N = N x (N + 1)/2

So, to find no. of days for snail to climb 210cm

N x (N +1 ) / 2 = 210
N x ( N + 1 ) = 420

We know 20 x 21 = 420

N = 20

So, in 20 days the snail will be able to climb 210cm

[Muffins]

Hi Dharma.


Sorry to be a buzzkill, but the actual question was 21 cm, not 210 cm…

[Dharma]

Muffins:

Hi Dharma.


Sorry to be a buzzkill, but the actual question was 21 cm, not 210 cm....

Hi Muffins,

To climb 21cm

N x (N + 1) / 2 = 21

N x (N + 1) = 42
6 x 7 = 42
N = 6 days

By using 210cm I was trying to show that it will be easier to solve the problem by finding a pattern. The listing method will
be just too long.

[imacsg]

Can you help to explain why is it wrong.


I am a 3 digit number.
My hundreds and tens digit are the same.
My ones digit is 4 more than my tens digit.
What number can I be?

My son writes 448, but the teacher marked it wrong and said the correct ans is 559. I thought the ans can be either 559, 448, 337, 226 or 115

Thanks

[singmathstutor]

imacsg:

Can you help to explain why is it wrong.


I am a 3 digit number.
My hundreds and tens digit are the same.
My ones digit is 4 more than my tens digit.
What number can I be?

My son writes 448, but the teacher marked it wrong and said the correct ans is 559. I thought the ans can be either 559, 448, 337, 226 or 115

Thanks

Based on the question that you have written, there are a few possible solutions as you have mentioned. Your son's answer is correct.

P.S. Can mod please transfer this post to the correct thread if needed. Thanks

[imacsg]

Hi All,

Thanks for the prompt reply. It is P3 question. I will check with the Teacher why he insists 559 the correct answer.

[markfch]

imacsg:

Hi All,

Thanks for the prompt reply. It is P3 question. I will check with the Teacher why he insists 559 the correct answer.

I've seen similar P3 math qn before. I suspect that there's a part of the information that is missing. Cos usually qn will limit to only one correct ans.